Question

which of the term of the sequence.
(x^2-y^2),(x+y),(x+y)/(x-y)........is x+y/(x-y)^9

Answer 1

first term, n=1
(x+y)/(x-y)^-1
note the denominator exponent = -1

2nd term , n=2
(x+y)/(x-y)^2
so, when n=2, den. exponent =0

similarly, n=3, denominator exponent = 1
......
continuing this way, when denominator exponent is 9, can u tell what n will be ?

Answer 2

x+y/(x-y)^9=(x^2-y^2) [1/(x-y]^n-1
=x+y/(x-y)^9=(x^2-y^2) 1/(x-y)^n-1
=(x+y)/(x^2-y^2(x-y)^9=1/(x-y)^n-1
=(x+y)/(x-y)(x+y)(x-y)9=1/(x-y)^n-1
=10=n-1
n=11?

Answer 3

N=11 IS CORRECT, YES :)