Solve by substitution: y = 2x - 3 y = -x + 1 Please help, I really don't get how to do this
@tHe_FiZiCx99
K, to substitute plug in y into the other equation, y = 2x - 3 y = -x + 1 -x + 1 = 2x - 3 Now can you solve that?
I'm still not sure, i know how to substitute but this question has just been confusing me :/ @tHe_FiZiCx99
The term itself says it :P Substitute in the " y = " equation into the other, I subbed the second equation into the first,
solve for x after you substitute
I got dis >.<
how can i solve for x though?
-x + 1 = 2x - 3 Add both sides x -x + 1 = 2x - 3 +x +x 1 = 3x - 3 Add both sides 3 to leave x alone, 1 = 3x -3 +3 +3 4 = 3x Divide to isolate x x = 4/3 NOW, to find Y plug in x into either equation and solve.
ok, whenever people say "solve for x" you just move the number around when problems are like this: -x + 1 = 2x - 3 - 1= - 1 -------------- -x = 2x -4 -2x=-2x ------------ -3x= -4 and so on, get it?
it does not matter which number you start first from either side. get me?
I'm still a little confused but I'm catching on
Ok, so now plug in 4/3 to find y, y = 2(4/3) - 3 First multiply 4/3 * 2
so y = -0.34
y = -1/3 :p -1/3 = -0.33333333333333333333333333333333
4/3 * 2 = 2.6666666666666666666666666666667 2.6666666666666666666666666666667 - 3 = -0.33333333333333333333333333333333
You plug both y and x to see if its a true statement, -1/3 = 2(4/3) - 3 -1/3 = -1/3 :P
-1.3 is y
and 2.6 is x
@tHe_FiZiCx99
never mind, -0.3 is y and -1.3 is x right?
No, you're not solving for them, your checking if they give you a true statement. x = 4/3 y = -1/3
oh, ok thank you soooo much!!
yw
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