Question

Physics! I think.

A plane is flying at 36 degrees south of west at 150 mi/h and encounters a wind FROM 75 degrees north of east at 55 mi/h. What is the planes new velocity with respect to the ground in standard position(east is the standard position)?

My answer:
South of West 223.8 degrees at 241.6 km/h

THANks XD

Answer 1

why are you giving your answer in km/h if the velocities are given in mi/h?

Answer 2

I'm skeptical of your answer on other grounds, too. If we convert 241.6 km/h to mi/h, the result is just a smidgeon over 150 mi/h. The plane has a tailwind roughly the same direction as it is flying, with the tailwind being > 1/3 the plane's speed, and it only goes a few mi/h faster?

Answer 3

Oh sorry, my answer was 241.6 mi/h. I have no idea why I wrote km

Answer 4

okay, even if the tailwind was exactly in the same direction, what is 150 + 55?

Answer 5

205?

Answer 6

right. does it make sense that a 55 mi/h tailwind can push the airplane from 150 mi/h to 241.6 mi/h, if 150+55 only equals 205?

Answer 7

nope you are right. I cant seem to these problems with cos sin and tan

Answer 8

its 196 mi/h?

Answer 9

yeah, that's about what I got from a careful diagram.

Answer 10

I didn't find the angle, but if you got the right magnitude, you should be able to do that :-)

Answer 11

oh ok it seems like i messed up right at the end when I was adding and doing the square root

Answer 12

Thank you