WILL GIVE MEDAL! I NEED HELP WITH THESE QUICK): if f(x)=2x^2-4x and g(x)=5-2x, evaluate f(x)-g(x) for x=5 A. 15 B. 5 C. 35 D. 20 If f(x) = 5x – 3 and g(x) = 3x – 3, find f(x) – g(x). A. 2x B. 8x – 6 C. 2x – 6 D. 8x
Line up the like terms of these two functions and then combine the like terms, remembering that you are subtracting g(x) from f(x). f(x) = 5x - 3 -g(x) = -3x -(-3) ----- = -------- = f(x) - g(x)
you just plug in the 2x^2 -4x into f(x) and 5-2x into G(x) so it's (2x^2-4x)-(5-2x) or 2x^2-4x-5-(-2x) then you plug in 5 for all of the x's...
so for the second question my answer would be C?
Josh and I are proposing the same thing; I just find it helps some people to line up like terms in columns. Josh is right in that you plug in x=5 to obtain f(5)-g(5). Kristina: Please show your work...support your choice with data.
all i did was subtracted 5-3 which equals 2 and 3-(-3) equals 6
im getting confused on how you explained it @Josh55 ):
when f(x)=2x^2-4x, that's saying you can just insert 2x^2-4x when you see f(x) and the same with g(x) and 5-2x
so f(x)-g(x) is really saying (2x^2-4x) - (5-2x)
And when x=5 that means whenever you see an x you can just switch it with a 5. Does that help?
so I would subtract 2x^2 from 5?
K: f(x) = 5x - 3 -g(x) = -3x -(-3) ----- = -------- = f(x) - g(x) Finish this work, and then substitute 5 for x.
when you put 5 in the place of x then 2x^2 will turn into 2*5^2 which is 2*25 or 50
but for that problem I don't have to substitute anything @mathmale
K: Have you read the problem statement carefully? if f(x)=2x^2-4x and g(x)=5-2x, evaluate f(x)-g(x) for x=5 Look at the last part of this sentence.
you gave me different numbers above lol @mathmale
okay so what would be the next step after we have 50 now? @Josh55
Are you sure I did that? If so, please show me where I gave you "different numbers."
can you see how you get 50?
if f(x)=2x^2-4x and g(x)=5-2x, evaluate f(x)-g(x) for x=5 I suggested that you add up like terms as follows: f(x) = 5x - 3 -g(x) = -3x -(-3) ----- = -------- = f(x) - g(x) Finish this work, and then substitute 5 for x. Last time I checked, 5x-3x=2x, and so, if x=5, 2x=2(5) =10. and that's it. Where'd that 50 come from?
I don't mean to abandon you, but unfortunately I have another commitment to attend to now. Good luck. See you both again on OpenStudy.
the first problem is the one you substitute the second problem you do not. you keep giving me the second problem and saying i have to substitute @mathmale lol
yes i do.. @Josh55
ok :) now do the exact same thing in (2x^2-4x) - (5-2x)
and that'll give you the answer
2(5)^2-4(5)-(5-2(5) so just solve it like that?
@Josh55
and the answer would be 35 ?:)
Yes, BUT be sure to ADD 2(5) at the very end because there's a double negative
way to go
thank you so much!
you're welcome, keep it up!
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