Let f(x)=4x^2+3. Evaluate lim h -> 0 (f(-3+h) - f(-3)) / (h)
Should both of those 3's in the last line not be the same sign?
Just fix it here, it's fine.
Finding the derivative?
It says evaluate and that's it. I assumed the answer would be 8 but it is not. I'm not sure what those threes are for.
Well f'(x) =8x, right?
yep
Hmm, does latex work?
The equation and drawing tools don't work, if that's what latex is.
Well if you're looking for the derivative, I can show ya how to get it, just give me a moment~
I'm just supposed to find what the limit is
This is the definition of the derivative f'(-3) evaluated at x=-3. That tells some of us the answer. Otherwise, carry out the operations [4(x+h)^2+ 3] -[4x^2 + 3}/h and let h go to zero, after the denominator cancels to 1.
So the answer is 1?
They may just know it as a limit, although they are looking for the derivative.
Ah answer is -24. Thanks. Didn't realize you could take the derivative and then plug in -3.
answer should come out to -24, but you need to derive it
Awe, I already derived.. did all that work for nothing >_>
A medal for the work.
Thank you c:
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