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Chemistry 16 Online
OpenStudy (anonymous):

How do you do empirical formulas? HELP ME PLEASE!!

OpenStudy (anonymous):

what information are you given?

OpenStudy (umlika):

emperical formula is calculated just by the lowest ratios of any reaction : suppose you have C6H12O6 so it's molecular formula would be 6:12:6 BUT it's emperical formula would be 1:2:1

OpenStudy (anonymous):

Determine the empirical formula of a compound containing 1.723 g of carbon, 0.289 g of hydrogen, and 0.459 g of oxygen.

OpenStudy (nikato):

first convert all 3 into moles

OpenStudy (anonymous):

0.1434637802 moles Carbon, 0.2861386139 moles Hydrogen, and 0.0286875 moles Oxygen

OpenStudy (nikato):

wait. im just gonna check quickly

OpenStudy (nikato):

ok. its correct. to make it easier. i think we should just round to the 4th digit after the decimal. so C-0.1435 H-0.2861 O-0.0287 now divide each by the smallest one which is pxygen

OpenStudy (anonymous):

C-5mol H-10mol O-1mol

OpenStudy (anonymous):

Now what do I do@nikato ?

OpenStudy (nikato):

so thats ur empiricul formula H10C5O. the numbers are suppose to be subscripts

OpenStudy (anonymous):

Thanks!!

OpenStudy (nikato):

no problem

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