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Mathematics 8 Online
OpenStudy (anonymous):

The population of a city is 83,945 and grows continuously at a rate of 1.3% each year. What is the approximate population of the city in 21 years? 110,295 105,626 110,279 106,862

OpenStudy (anonymous):

thanks:)

OpenStudy (anonymous):

i have a bunch of questions like this one can you tell me the formula for it

OpenStudy (anonymous):

"Pert" is the formula P stands for principles. E stands for e. R stands for rate. and T stands for time.

OpenStudy (anonymous):

The population of a town is 68,172 and declines continuously at a rate of 3.6% each year. What is the approximate population of the town in 14 years? 112,847 33,813 40,802 41,183 I also have these questions

OpenStudy (anonymous):

when it says "continuous" it wants you to use the Pert Formula.

OpenStudy (anonymous):

the principle is 68172 rate is .036 and time is 14

OpenStudy (anonymous):

rate is -.036

OpenStudy (anonymous):

So i know i have to subtract and I know I have to multiply and I think the problem is supposed to go something like this 68172*0.036 ...but now i am not sure what to do with the 14

OpenStudy (anonymous):

this is how i did it, correct me if I'm wrong @CGGURUMANJUNATH 68172e^(-.036*14) = your answer

OpenStudy (whpalmer4):

@CGGURUMANJUNATH you aren't doing these problems correctly!

OpenStudy (anonymous):

im confused who is doing it right

OpenStudy (anonymous):

i am.

OpenStudy (anonymous):

do you have a TI-89 calc?

OpenStudy (whpalmer4):

@annasjuice is — these are exponential growth/decay, so you need an exponential (or repeated multiplication) to compute them.

OpenStudy (anonymous):

no, I dont have that kind of calculator. I just have the EL-501W

OpenStudy (whpalmer4):

the "Pert" formula isn't multiplication, it's P*e^(-rt) where e is the base of the natural logarithm, approximately 2.71828 That first problem, with the 1.3% growth each year. It's 1.3% of the population at the beginning of the year, so the amount added in the 2nd year is larger than that added in the first, and the amount added in the 3rd year is larger than that added in the second, and so forth. It's just like compound interest.

OpenStudy (anonymous):

so I use that formula? y'all have lost me but I think im finding yall

OpenStudy (anonymous):

i'm no sure how you can do it without the TI-89 calc. you can download these calc online. and yes, it is the P*e^(rt) formula. but since your problem says, "declines continuously at a rate of 3.6%" it would be like P*e^(-rt). so, 68172e^(-.036*14) = final answer

OpenStudy (anonymous):

do you get it? knowing that formula is important

OpenStudy (anonymous):

it helps

OpenStudy (anonymous):

ok so i have the formula, So can u show me how to work it

OpenStudy (anonymous):

68172e^(-.036*14) ^ multiply this 68172e^(-.504) since you don't have a calculator... base e= 2.71828 68172*(2.71828)^(-.504) <-- put this in the calculator and you'll get your answer

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