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Mathematics 18 Online
OpenStudy (anonymous):

Calculate the calories needed to freeze 35 g of water and indicate whether heat is absorbed or released.

OpenStudy (anonymous):

oh thats a chemistry question thou but anyways,

OpenStudy (anonymous):

try the formula Q = mL

OpenStudy (anonymous):

@jigglypuff314 help here

jigglypuff314 (jigglypuff314):

erm heat change in freezing of water=-79.72 cal/g freeze 35 g of water=(35)(-79.72)=-2790.2 calories (heat absorbed) http://www.transtutors.com/questions/tts-heat-115489.htm

OpenStudy (anonymous):

Q=mLf bot the latent heat of fusion of water is 79.8 cal/g. => Q=79.8 cal/g*35g=2793 cal. as the change of state is from liquid to solid heat is released!!!

jigglypuff314 (jigglypuff314):

yeah logic mistake on my part, sorry. think like when you're cooling something (turning water into ice) you should be taking heat away from it to do that so heat should be released :)

OpenStudy (anonymous):

THANK YOU

jigglypuff314 (jigglypuff314):

glad we could help :) Best of Luck for your journey on OpenStudy.

OpenStudy (anonymous):

Jiggly also give her link to chemistry group

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