Question

sin^2xtan^2x

Answer 1

tan^2(x) - sin^2(x)
sin^2(x)/cos^2(x) - sin^2(x)
[sin^2(x) - cos^2(x)sin^2(x)]/cos^2(x)
sin^2(x)(1 - cos^2(x))/cos^2(x)
sin^2(x)sin^2(x)/cos^2(x)
tan^2(x)sin^2(x)

Answer 2

I need to rewrite in the power reducing formula.

Answer 3

Richie: Without instructions, this problem is open to interpretation / misinterpretation by potential helpers.

Oh, now I see what your aim is. Give me a moment.

Answer 4

Can you type out the "power reducing formula" for (sin x)^2, to demonstrate that you know it?

Answer 5

1-cos2x all over 2

Answer 6

that's correct except for a sign error.

Please write your identity as


(sin x)^2 = .... ?

Answer 7

What do you mean? Can you help me

Answer 8

Mea culpa! I'm all wet. Your formula is fine. I was just asking that you label it:

(sin x)^2 = (1-cos 2x)/2

Is there a similar, power reducing formula for (tan x)^2?

Answer 9

Yes, it is (tan)^2x= (1-cos2x)/(1+cos2x)

Answer 10

You there?

Answer 11

Yes. Now please put together both of the power reduction formulas. Whether or not you choose to multiply after having done that is up to you. Does this make sense to you? if not, what further info do you need to complete this problem solution?

Answer 12

I do recommend reducing your result to its simplest possible form.

Answer 13

so its (1-cos2x/2)(1-cos2x/1+cos2x)

Answer 14

Hold; I'm checking my own work.

Answer 15

Yes, your result is fine. If you wanted to, you could multiply the numerators and obtain

[ (1-cos 2x)^2 ] / [1 + cos 2x].

Answer 16

Any further questions related to this problem?

Answer 17

I think there is another step

Answer 18

i have to find the result in terms of first power of cosine

Answer 19

Actually, i think you simplified it enough.

Answer 20

glad for this opp to work with you! Thank you for the medal.

Answer 21

What did you do with the denominator of 2?

Answer 22

I simply left it where it is. Can't eliminate that 2.