N messages are sent to N computers. The messages get mixed up and are distributed randomly. What is the mean number of messages received? [Consider N = 3 ]
if three messages are randomly sent to three computers, it will be 3 x 3 but since you are looking for the mean, that would be 9/3
I don't really understand why did you say 3 x 3 ? Could you please explain further ?
Wait so you're sending 3 messages to 3 computers but they get mixed up. So did you plan to send one to each? Is there a constriction as to how many messages are sent to each computer?
That's all there is to the question. Since, it is distributed randomly, i don't think there is a constriction as to how many messages are sent to each computer.
try MAPPING the scenario with no restriction of the same message to be sent to different computers message 1 to computer 1, 2 or 3 message 2 to computer 1, 2 or 3 message 3 to computer 1, 2 or 3 with restriction create your own
So basically, each message will have 1/3 chance of getting sent to one computer - So how do i do the mean o.O ?
I was thinking, if there are no restrictions to how many messages are sent to each computer, couldn't there be an infinite number of messages to at least 1 computer? That's where I'm stuck.
Okay, Maybe i got that part wrong and that distributed randomly actually means one message per computer ! Then how will you proceed ?
...if you can only get 1 message per computer then the mean would just be 1...
Sorry I can't really help. If there were restrictions I can probably work it out but this is kinda weird. Good luck.
Okay ! Thanks Anyway ! :)
You're welcome. :)
if one message can only be sent to a unique computer, then the scenario changes map it again scenario 1 message 1 goes to computer 1 message 2 goes to computer 2 message 3 goes to computer 3 scenario 2 message 2 goes to computer 1 message 1 goes to computer 2 message 3 goes to computer 3 scenario 3 message 1 goes to computer 3 and so on and so forth
considering that you're doing probability, you might want to consider Little's Law
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