The position vector r of a particle in an xy plane is given by r=(2t^3-5t)i+(6-7t^4), with vector r in meters and t in seconds. In unit vector notation calculate r? I'm completely lost how to get the unit vector where there is no t variable because we're not given t or anything. Please help.
one sec while I write it out
What is meant by "unit vector notation" ? Is it another name for polar coordinates?
a unit vector is a vector whose length is 1
@Vincent-Lyon.Fr are you familiar with i, j, and k to represent x, y, and z respectively
Yes I am, but I am puzzled because r=(2t^3-5t)i+(6-7t^4)j is already resolved along i and j. (both unit vectors) What I do not understand, is what kind of r = ...??... type or formula is expected here.
actually, i didn't see a j...
yea unit vector would just be like r=xi+yj the answer in the back is r= 6m i - 106m j
could you write out the whole question? or is that it?
oh and I meant for there to be a j originally
and that's the whole question for part a at least
ok, can you write the WHOLE question? all parts?
They must give you the value of t somewhere in the question.
maybe there's some information that is provided in the other parts also, i think I recognize that question, is your book by any chance Serway-Jewett, physics for scientists and engineers?
That's what I'm confused about is that there is no t given like in the example at the beginning of the chapter, and it says it's supposed to be an easy problem... And it's actually Fundamentals of Physics by Jearl Walker
Regardless, please type out the full question including parts b, c, etc Perhaps we may see something that you missed
The position vector r of a moving particle in an xy plane is given by vector r=(2t^3-5t)i+(6-7t^4)j, with vector r in meters and t in seconds. In unit-vector notation, calculate a)vector r, b) vector v (velocity), c) vector a (acceleration) for t=2.0s
ok I think I just should have read all the way through cuz they gave t
t=2
:)
wellp I guess I can get on with my homework now, thanks!
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