Question

Needed help with this graph

Answer 1

http://puu.sh/6zcRE.png

Answer 2

@ranga @agent0smith

Answer 3

This graph really had me confused agent0smith

Answer 4

@precal

Answer 5

Have you started trying to identify either the line or the quadratic equation?

Answer 6

graphs, ive always had a problem it really confuses me, just get me started so i can know where i start

Answer 7

On the line you have two sets of coordinates, shown as (x-coordinate,y-coordinate), you can plug these coordinates into the equations to see which it works out for

Answer 8

yeah, im lost

Answer 9

Another way is to look at the quadratic function, this is the function that includes the x^2 term. When x = 0, you can see y = 3.. which of the equations is this true for?

Answer 10

Do you understand what I'm trying to say? I've not learned this stuff in english... which isn't really my first language

Answer 11

y = x2 + 5x − 3
6x + y = 27

Answer 12

Look at that first equation you typed there, y = 2x + 5x - 3.
If x = 0, y = -3, this does not agree with what we see on the graph (the curved function)

Answer 13

x = 3, y = 3 is what we see on the graph, so y = x^2 + 5x + 3 is better

Answer 14

x = 0, y = 3*** I meant

Answer 15

i dont understand where your getting all this information

Answer 16

The graph shows the x-axis and y-axis, yes?

Answer 17

x is horizontal, y is vertical

Answer 18

Okay so looking at the curved function on the graph, when x is 0, we see that y is 3. Plugging this into y = x^2 + 5x + 3 gives us 3 = 0^2 + 5*0 + 3, which means 3=3 which is true

Answer 19

By plot inspection, when x = 0, y =3. That leaves quadratics 2 and 3.

When y = 0, x must be negative.
That leaves quadratic 3 and it's line.