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Mathematics 21 Online
OpenStudy (anonymous):

Can anyone help me with figuring out number 9? I had to upload it here because I couldnt find another way of showing the problem. Geometry Help. http://prntscr.com/2mv8jo

OpenStudy (anonymous):

m=6 n=4.5

OpenStudy (anonymous):

Keiichi, how did you get those answers?

OpenStudy (anonymous):

3/2 = m/4=n/3 3/2= 1.5 6/4= 1.5 4.5/3= 1.5 there are other ways you can solve this, but this is the easiest.

OpenStudy (anonymous):

That really didnt help me to be honest. What do you mean by 3/2 = m/4 = n/2

OpenStudy (anonymous):

?*

OpenStudy (anonymous):

ugh sorry, have you learned the side-splitter theorem yet?

OpenStudy (anonymous):

No. But I figured out how you got 6 for M. Im going to try and find N and see if youre correct.

OpenStudy (anonymous):

Yeah. I got 4.5 for N also.

OpenStudy (anonymous):

How would i do 10?

OpenStudy (anonymous):

this was my work for problem 9 can you take a better picture for number 10, please?

OpenStudy (anonymous):

Yeah. Hold on one sec.

OpenStudy (anonymous):

OpenStudy (anonymous):

Can you see that one?

OpenStudy (anonymous):

i hope this help?? tell me if you have any problem reading the handwriting

OpenStudy (anonymous):

I can see that you use a different method than what I am learning. i am guessing that is a more advanced/easier way of doing this type of mathematical problem in geometry?

OpenStudy (anonymous):

But I still need some help.

OpenStudy (anonymous):

alright, but im also doing work of my own so my replies might be a bit slow. ;;

OpenStudy (anonymous):

I need help with these 3 if you could please help me. And its fine if you take some time to reply.

OpenStudy (anonymous):

Im patient lol.

OpenStudy (anonymous):

i'll do my best. ^o^

OpenStudy (anonymous):

Yeah. I have no idea what to do for 10. Lol.

OpenStudy (anonymous):

I mean 11*

OpenStudy (anonymous):

#11

OpenStudy (anonymous):

Thats number 10 lol

OpenStudy (anonymous):

oops

OpenStudy (anonymous):

sorry

OpenStudy (anonymous):

12 is confusing.

OpenStudy (anonymous):

it's the same actually

OpenStudy (anonymous):

13 is something else. I dont think Ive learned that yet to be honest.

OpenStudy (anonymous):

i've never seen this type problem while learning the side-splitter theorem...

OpenStudy (anonymous):

Lol. I guess I wont do it. I dont even know what the side-splitter theorem is either.

OpenStudy (anonymous):

But do you know how to do these type of problems? These seem easier but I dont understand that much.

OpenStudy (anonymous):

33/22=h/12 22*h=396 /22 /22 h=18

OpenStudy (anonymous):

Is that the side splitter theorem?

OpenStudy (anonymous):

It's somewhat similiar. this is the side-splitter theorem http://www.mathwarehouse.com/geometry/similar/triangles/side-splitter-theorem.php

OpenStudy (anonymous):

Could you break down how you got the answer for number one for me? Because in text, its not as easy to keep up. Like these, I dont get how to do for some reason. The other ones were easier and i checked them the way I would usually do it myself.

OpenStudy (anonymous):

alright. 33 and 22 are the corresponding sides of the 2 triangles so lets put it as a fraction. 33/22 (it's easier if you write it on paper) h and 12 are the corresponding altitudes of the triangles so lets put it as h/12 h and 33 are the numerators because they belong to the same triangle.

OpenStudy (anonymous):

now you should have something like this 33 = h 22 12

OpenStudy (anonymous):

cross multiply and solve for h

OpenStudy (anonymous):

Just curious, are you taking honor geometry?

OpenStudy (anonymous):

Yes. But the thing about that is I recently transferred schools due to the fact that my old school had a terrible Geometry honors teacher that would speak about his personal life and would never teach. So I transferred schools mid way through the year and im kind of lost but I am trying my best to keep up with my new teacher. Ive picked up a couple of things so far but not all the things I should know. Im great at math btw but its just that Im a little bit confused.

OpenStudy (anonymous):

I understand, i left the country the last few weeks and it's been tough trying to catch up.

OpenStudy (anonymous):

Ugh. Yeah man. Its kind of tough on me because I got to start over and make new friends and stuff because in my old school I was so confined with the same people for about 5 years or so because I went to the same school for middle school and part of high school.

OpenStudy (anonymous):

But Ive been trying my best to keep up.

OpenStudy (anonymous):

Could you help me out with this one? And thanks for being so patient with me lol. I havent been on this website in 2 years or so.

OpenStudy (anonymous):

alright, you might want to write this down. this is easier than the last one

OpenStudy (anonymous):

Wouldnt it be easier just to send a picture? But if you want to write it down then sure.

OpenStudy (anonymous):

or type it I mean.

OpenStudy (anonymous):

(triangle ski is the denominator)

OpenStudy (anonymous):

i was gonna do that but I literally wasnt so sure.

OpenStudy (anonymous):

It's worth trying, you can always fix it if it's wrong. ( ´ ▽ ` )

OpenStudy (anonymous):

I know lol. This one i dont get. Im thinking CS but Im just guessing. I havent really tried.

OpenStudy (anonymous):

it is CS there's really not an explanation for this but PI is cut in half

OpenStudy (anonymous):

Lol. What the heck. I thought I was almost done but I have 11 more questions to go. FML.

OpenStudy (anonymous):

SI one of the half, is cut in half so seeing that CS and CL share the same point (c) and is located on the halves of SI. It should be congruent to CS.

OpenStudy (anonymous):

Yeah. That one seemed easy.

OpenStudy (anonymous):

Oh my god. If this isnt too much to ask for, can you please help me out? Im so lost. I gotta talk with my teacher about this because Ive never had so much problem with something before.

OpenStudy (anonymous):

I'll try

OpenStudy (anonymous):

Yeeahh. Im lost. Lol.

OpenStudy (anonymous):

OpenStudy (anonymous):

for LEG it's 364 btw

OpenStudy (anonymous):

So for 4 FD=15?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Alright.

OpenStudy (anonymous):

Im so close to finishing.

OpenStudy (anonymous):

that's good

OpenStudy (anonymous):

These seem a little bit easier but help me out. Im gonna try and do what I can and see if i get it right.

OpenStudy (anonymous):

Im thinking for 9 x=5 but not so sure.

OpenStudy (anonymous):

Yeah. I dont know how to do this.

OpenStudy (anonymous):

it's 16

OpenStudy (anonymous):

20 = v 45 36

OpenStudy (anonymous):

45v = 720

OpenStudy (anonymous):

v = 16

OpenStudy (anonymous):

Would you do the same for 8? Like 51/34=y/40?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Would y be 60?

OpenStudy (anonymous):

And help me out with 9. I dont know how to do that one.

OpenStudy (anonymous):

yes, y would be 60 for 8

OpenStudy (anonymous):

Okay. I got that right.

OpenStudy (anonymous):

you're dealing with a whole triangle and a half triangle in 9

OpenStudy (anonymous):

so 5?

OpenStudy (anonymous):

15/12 and 10/x would work

OpenStudy (anonymous):

15x = 120 x=8

OpenStudy (anonymous):

Yeah I got that right now. lol

OpenStudy (anonymous):

I need like 5 more and im done bothering you

OpenStudy (anonymous):

Idk how to do 10 because it has no numbers.

OpenStudy (anonymous):

K has square root and idk

OpenStudy (anonymous):

11* not k

OpenStudy (anonymous):

a/b= p/q bc a p shares the same triangle and b q shares the other

OpenStudy (anonymous):

so a/p = b/q

OpenStudy (anonymous):

k = 3 √3

OpenStudy (anonymous):

So the answer for 11 is k=3 sqrt 3?

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