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Suppose f(x) is continuous on [2,8] and −2≤f′(x)≤4 for all x in (2,8). Use the Mean Value Theorem to estimate f(8)−f(2).
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Well, based on mean value theorem, we know that f'(x*) = [ f(8)-f(2) ] / [ 8 - 2]
We we start with: −2 ≤ [f(8)-f(2)] / (8-2) ≤ 4
yes but we aren't told what f(x) is equal to..
We don't need f(x).
We are solving for f(8)-f(2)
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If we let a = f(8)-f(2) then we have −2 ≤ a / (8-2) ≤ 4
this is the exact question
Do you want an exact answer or something? I have you an inequality and all you have to do is simplify it.
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