Simplify the given expression. (6 + 2i) − (8 − 3i)
ahhh must be in ai+b or a+bi form
−2 + 5i −2 − i 8 + 5i 8 − 5i
distribute the negative on the right hand side of the equation ... combine like terms.. there's the format ^^
(6 + 2i) − (8 − 3i) 6+2i-8+3i = -2+5i
how'd you add them together? i tried foil but i didnt get the right thing
no there's no foil in here. just normal subtraction and combining like terms
foil works for (x+y)(x-y) no sign in the middle
ohh
can you help with one more? Simplify the given expression. 2 divided by the quantity of 2 plus 5i
hmm :/ I can't see it very well
argh I forgot how those work...
I know you can't split them up... nooo that breaks the rules
Couple of things to know here: 1) i=Sqrt(-1), i^2=-1 2) (a+b)(a-b) = a^2 - b^2, with no middle term 3) the goal of this problem is to eliminate the complex number 2 +5i from the denominator. 4) 2-5i is called the "conjugate" of 2+5i. 5) Applying principles from (1) and (2), above, (2-5i)(2+5i)=4-25i^2 which simplifies to 4-25(-1) = 29. 6) multiply both numerator and denominator of the given expression by the conjugate in (4) and simplify the result. 2(2-5i) 2(2-5i) ------- = --------- is the simplest form the answer you want. 4-25(-1) 29 There's no real benefit from multiplying out 2(2-5i).
Notice how the denominator is now real, whereas before it was complex.
so you just multiply the numerator by the conjugate? then simplify fro mthere?
Also notice that the first problem you presented was one in subtraction of complex numbers; the second was more complicated because of the multiplication of complex numbers required. @skipper16: Multiply BOTH the numerator and the denominator of the given fraction by the conjugate (2-5i).
This process may be referred to as "rationalizing the denominator".
now I remember...
Hmm
Thank you very much for the medal.
you're welcome thanks for the help
:O where's my medal?
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