Question

Is this an identity or no solution?
6-6x=-6x-6

Original Problem:
3(2-2x)=-6(x-1)

Answer 1

6-6x = -6x+6
it's an identity just the right side is written differently

Answer 2

6-6x=-6x-6

6-6x+6x=-6x-6+6x ... add 6x to both sides

6 + 0x = 0x - 6

6 + 0 = 0 - 6

6 = -6 ... which is always false

so there are no solutions (this is a contradiction)

Answer 3

So is it no solution?

Answer 4

however, for the original equation

3(2-2x)=-6(x-1)

3(2)+3(-2x)=-6(x)-6(-1) ... distribute (remember to distribute to EVERY term inside)

6 - 6x = -6x + 6

6 - 6x = 6 - 6x

and we can see the two sides are identical...so we have an identity which means we have infinitely many solutions

Answer 5

UGH YOU SCARED ME MAN! DON'T DO THAT >:O

Answer 6

Notice how 6-6x=-6x-6 (what you posted first) and 6 - 6x = -6x + 6 (what you get when you distribute) are different

Answer 7

no, 6-6x=-6x-6 is different from 6 - 6x = -6x + 6

Answer 8

so it is no solution.. my bad ^^

Answer 9

the negative sign on the right threw everything off when you distribute

Answer 10

If the original problem is 3(2-2x)=-6(x-1), then you distribute things out to get 6 - 6x = -6x + 6

Answer 11

That is an identity which leads you to infinitely many solutions (basically all real numbers)

but if the original is 6-6x=-6x-6, then it's going to lead to a contradiction