Question

solve for x.
0=(10+2x)(16+2x)-320
i keep getting not factorable! help?

Answer 1

4 x^2+52 x-160= 0 solve using the quadratic formula

Answer 2

yes i got that too but it doesn't work. trust me. i tried quadratic formula.

Answer 3

It just might not be giving you a 'nice' answer. (Nice here meaning an integer of fraction solution)

No matter, a solution is a solution.
Now, could you state the quadratic formula, just so we're clear?

Answer 4

x = -b +/- (square root of:) b^2 + 4ac and everything divided by 2a

Answer 5

b^2 - 4ac in the square-root, not b^2 + 4ac
ok?

Good, now what are your values for a, b, and c?

Answer 6

sorry yeah thats what i meant. and values are: a=1, b=13, and c=-40, when factored

Answer 7

Don't think so.
Check on Satellite's simplification, and tell me what a, b, and c are.

Answer 8

0=(10+2x)(16+2x)-320
0=(160+20x+32x+4x^2-320
0=4x^2+52x-160
0=4(x^2+13x-40)
0=x^2+13x-40
do you see where i got the values from?

Answer 9

oh okay then, sorry ^_^

Well then, just plug in :)

Answer 10

okay :P