Question

Discontinuity

Answer 1

what value is a discontinuity of

Answer 2

all rational functions are continuous on their domains
question is identical to "what is the domain?"
set the denominator equal to zero and solve for x

Answer 3

hmm so x^2+7x+1 = 0

Answer 4

denominator

Answer 5

aka bottom of the fraction
you cannot divide by zero, so set
x^2 + 2x + 15 = 0 and solve for x
this one factors

Answer 6

oops i meant x^2 + 2x -15 = 0

Answer 7

I cant add 15 on both sides?

Answer 8

@satellite73

Answer 9

@Mertsj

Answer 10

Factor and set each factor equal to 0 and solve each equation.

Answer 11

I cant remember how

Answer 12

@agent0smith hey I was wondering if yu add 15 on bith sides

Answer 13

@jim_thompson5910

Answer 14

To factor x^2 + 2x -15, find two numbers that multiply to -15 and add to 2

Answer 15

3 and -5

Answer 16

3 + (-5) = -2, but we want them to add to +2

Answer 17

-3 +5?

Answer 18

better

Answer 19

so x^2 + 2x -15 factors to (x-3)(x+5)

Answer 20

x^2 + 2x -15 = 0

(x-3)(x+5) = 0

x = ?? or x = ???

Answer 21

x = -3 or x= 5?

Answer 22

x-3 = 0 ----> x = ???

Answer 23

x = 3!

Answer 24

yep, what's the other solution?

Answer 25

x=-5

Answer 26

so x = 3 and x = -5 make x^2 + 2x -15 equal to zero

those are the values that produce a discontinuity (since you cannot divide by zero)

Answer 27

ur amazing thanks . I have a couple more if u d like to help get them out the way

Answer 28

I can help with one more

Answer 29

find the horizontal or oblique asymptote of

Answer 30

Because the degree of the numerator (2) is larger than the degree of the denominator (1), you will have an oblique asymptote

Answer 31

You will need to use polynomial long division to find the equation of the oblique asymptote

Are you familiar with polynomial long division?