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Mathematics 6 Online
OpenStudy (anonymous):

Advance Trig Help

OpenStudy (anonymous):

Prove the identities sin(theta)=4/5

OpenStudy (anonymous):

Find the five other trigonomic values for (theta)

OpenStudy (anonymous):

well. you know that sin is y/r with r being the hypotenuse

OpenStudy (anonymous):

And y is the opp?

OpenStudy (anonymous):

yes. but since you dont have an angle to work with we dont care about opposite for this problems. just in terms of x y and r

OpenStudy (anonymous):

so draw your triangle with the y as 4 and they hyp as 5 and it should be obvious

OpenStudy (anonymous):

Oh. So what it means by other values is the degrees and other sides?

OpenStudy (anonymous):

umm hmm. no you just make a triangle. find all three sides. and write them in terms of x y and r sin is y/r cos is x/r tan is y/x csc is r/y sec is r/x cot is x/y

OpenStudy (anonymous):

so you know the y and r. use the pythagorean theorem x^2+y^2=r^2 to get your x value

OpenStudy (anonymous):

(2)^2+(4)^2=r^2?

OpenStudy (anonymous):

uhh. where did the 2 come from. it was 4/5 with 5 being r and 4 being y

OpenStudy (anonymous):

lol, ops

OpenStudy (anonymous):

x^2+4^2=5^2

OpenStudy (anonymous):

x^2+4^2=1^2?

OpenStudy (anonymous):

pythagorean triple. but if your already confused i would ignore what i just said

OpenStudy (anonymous):

where did the 1 come from?

OpenStudy (anonymous):

it should be a 5 lol.

OpenStudy (anonymous):

Im getting the radius of the circle mixed up x_x

OpenStudy (anonymous):

y/r , y=4 r=5 ?

OpenStudy (anonymous):

x^2+4^2=5^2?

OpenStudy (anonymous):

yes.

OpenStudy (anonymous):

So its 3?

OpenStudy (anonymous):

x is 3 now you know x y and r and knowing your ratios in terms of x y and r you can fill all of them now

OpenStudy (anonymous):

Wow! It seems much easier that way

OpenStudy (anonymous):

yes, indeed. it is easy.

OpenStudy (anonymous):

sin is 4/5 cos is 3/5 tan is 4/3 csc is 5/4 sec is 5/3 cot is 3/4

OpenStudy (anonymous):

perfect.

OpenStudy (anonymous):

Wait a minute...

OpenStudy (anonymous):

Somethings not right..

OpenStudy (anonymous):

How would I know the combinations for sin,cos,tan,csc,sec, and cot?

OpenStudy (anonymous):

Do I have to memorize them?

OpenStudy (anonymous):

you will have to in terms of x y and r opp adj hyp and the unit circle definitions

OpenStudy (anonymous):

Thats over 6 diff combinations @_@

OpenStudy (anonymous):

its easy. just remember sin cos and tan. and the others are reciprocals.

OpenStudy (anonymous):

k

OpenStudy (anonymous):

At least I know what to work on, lol.

OpenStudy (anonymous):

ya. get on pauls online math notes and print off his trig cheat sheet. will save your life if you memorize all the identities and the unit circle and all the function definitions.

OpenStudy (anonymous):

Fore Sure. For the next question Find the six trigonometric values of the angle whose terminal side lies on the point (3,-5)

OpenStudy (anonymous):

Isnt it the same thing?

OpenStudy (anonymous):

can you tell me what quadrant that is in?

OpenStudy (anonymous):

and. it is not the same thing.

OpenStudy (anonymous):

Quadrant?

OpenStudy (anonymous):

uuuuuuh ya the quadrants. you dont know the quadrants? 1-2-3-4?

OpenStudy (anonymous):

Oh, you are testing me. I thought you were asking for more info on the question

OpenStudy (anonymous):

ya. where does that point lie on the rectangular coordinate system

OpenStudy (anonymous):

quadrants 1 and 2?

OpenStudy (anonymous):

you know the x is 3 and the y is -5. and no it would be in quadrant 4.

OpenStudy (anonymous):

Pos Pos, and neg neg qaudrents

OpenStudy (anonymous):

use the pythagorean theorem on the x and y to get r. then write out all of the rest

OpenStudy (anonymous):

with 3,-5 you will be facing down to the right on the grid. into quadrant 4 where your x value is positive and your y value is negative.

OpenStudy (anonymous):

Im misunderstanding all of your questions. It must be frustrating. Srry.....

OpenStudy (anonymous):

im not frustrated at all. im terrible at wording and explaining stuff.

OpenStudy (anonymous):

so knowing what you know now. what do you have for r

OpenStudy (anonymous):

So 3^3+-5^2=r^2?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so 9+25=r^2?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

34=r^2 sqrt(34)=r?

OpenStudy (anonymous):

yes.

OpenStudy (anonymous):

Are the six trig values the ones from before? Soo all we need to do now is plug in?

OpenStudy (anonymous):

sin-y/r cos-x/r tan-y/x csc-r/y sec-r/x cot-x/y now plug and chug. i always rationalize denominators also.

OpenStudy (anonymous):

sin- -5/(sqrt)34 cos- 3/(sqrt)34 tan- -5/3 csc-sqrt(34)/-5 sec-sqrt(34)/3 cot- 3/-5

OpenStudy (anonymous):

keep in mind your in quadrant 4 and what your signs will be in 1 all pos in 2 students(sin) positive in 3 take(tan) positive in 4 calculus(cos) positive

OpenStudy (anonymous):

ya, as long as you dont have to rationalize the denominators, that is correct.

OpenStudy (anonymous):

k

OpenStudy (anonymous):

Find the value of (theta) cot(theta)=1

OpenStudy (anonymous):

inverse cot to both sides.

OpenStudy (anonymous):

cot^-1(1)

OpenStudy (anonymous):

cot^-1(1)=theta

OpenStudy (anonymous):

What os theta though?

OpenStudy (anonymous):

theta will be whatever your calculator spits out for the input i posted above.

OpenStudy (anonymous):

inverse tan (1) or arctan

OpenStudy (anonymous):

Itsna little bit harder to type since im using my phone

OpenStudy (anonymous):

well. if you wanna do it on paper. you know that when tan or cot is positive 1 you are in quadrant 1 or 3 at a 45 degree angle, right?

OpenStudy (anonymous):

so your possible angles are 45 and 225

OpenStudy (anonymous):

k

OpenStudy (anonymous):

do you see how i did that? if cot is positive 1 its q1 or 3. theyre 1 whenever you have a 45-45-90. making cot45=1 and the reference angle 45 from the x axis is 1 as well.

OpenStudy (anonymous):

So theta is a variable then?

OpenStudy (anonymous):

yes. you solve for it using inverse operations. just like an algebra problem.

OpenStudy (anonymous):

What about sin(theta)=1/2?

OpenStudy (anonymous):

You would inverse to have sin(1)^-1=theta?

OpenStudy (anonymous):

do you want theta or the 6 trig functions? if you want theta, of course use inverse sin

OpenStudy (anonymous):

, I want the value of theta

OpenStudy (anonymous):

Im still a bit confused on this one. How wouls you get a number that equals theta? Is it just degrees?

OpenStudy (anonymous):

if your calculator is in degrees it will.

OpenStudy (anonymous):

Wait... woudnt it be sin(30)=1/2?

OpenStudy (anonymous):

yes. now your getting the feel for your 30 60 90 triangles.

OpenStudy (anonymous):

Now on to the last ones

OpenStudy (anonymous):

FInd the amplitude,range,and domain of y=cos((1/2)x)-2

OpenStudy (anonymous):

you you know which numbers do what to the graph?

OpenStudy (anonymous):

I know that amplitude is similar to an asymtote

OpenStudy (anonymous):

2pi/p

OpenStudy (anonymous):

hmmmm. amplitude is the height of the graph. it is whatever is in front of cos

OpenStudy (anonymous):

p/4

OpenStudy (anonymous):

multiplied to cos that is.

OpenStudy (anonymous):

amplitude is 1

OpenStudy (anonymous):

2pi/(1/2)=period?

OpenStudy (anonymous):

that is correct for period

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