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Mathematics 21 Online
OpenStudy (anonymous):

can a 3x5 coefficient matrix be consistent if it has 3 pivot columns?

OpenStudy (usukidoll):

3 rows five columns... depends on the situation

OpenStudy (anonymous):

okay column 1, 2 and 5

OpenStudy (usukidoll):

I guess as long as the last two rows are all 0's errrrrrrrrrrrrrr. you mean that column 1 2 and 5 have leading ones?

OpenStudy (usukidoll):

what do you have for 3 and 4?

OpenStudy (anonymous):

well is there a situation were the matrix is not consistent?

OpenStudy (usukidoll):

yeah when there are a row of zeros but on the right hand side there is a number

OpenStudy (usukidoll):

so 0 0 0 0 0 line 3 inconsistent system

OpenStudy (usukidoll):

many solutions would be 0 0 0 0 0 line 0 consistent also has this ^

OpenStudy (anonymous):

ohh yea i now what nonzero row is

OpenStudy (anonymous):

but if you have a row that is zero then you cant have 3 pivot columns

OpenStudy (usukidoll):

well the pivot is a leading one... doesn't it go from the right and to the bottom 1 0 0 0 0 line 2 0 1 0 0 0 line 3 0 0 1 0 0 line 4 0 0 0 1 0 line 5 0 0 0 0 1 line 6 but based on yours 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1

OpenStudy (usukidoll):

I guess if you switch the rows.. even though it looks kind of whacky, the rules aren't broken. that leading one is going to the bottom and right

OpenStudy (usukidoll):

1 0 0 0 0 0 1 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0

OpenStudy (anonymous):

girl a 3x5 is 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

OpenStudy (usukidoll):

oh man thanks... sorry I was multitasking

OpenStudy (usukidoll):

lol I did a 5 x 5 my bad 1 0 0 0 0 0 1 0 0 0 0 0 0 0 1

OpenStudy (usukidoll):

there.. looks decent to me.

OpenStudy (usukidoll):

now lets write it in augmented matrix 1 0 0 0 0 line 3 0 1 0 0 0 line 4 0 0 0 0 1 line 5 looks consistent to me

OpenStudy (loser66):

3equations, 5variables, the rank of the matrix is at most 3, so, if it has 3 pivot columns, it is consistent. why not?

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