can a 3x5 coefficient matrix be consistent if it has 3 pivot columns?
3 rows five columns... depends on the situation
okay column 1, 2 and 5
I guess as long as the last two rows are all 0's errrrrrrrrrrrrrr. you mean that column 1 2 and 5 have leading ones?
what do you have for 3 and 4?
well is there a situation were the matrix is not consistent?
yeah when there are a row of zeros but on the right hand side there is a number
so 0 0 0 0 0 line 3 inconsistent system
many solutions would be 0 0 0 0 0 line 0 consistent also has this ^
ohh yea i now what nonzero row is
but if you have a row that is zero then you cant have 3 pivot columns
well the pivot is a leading one... doesn't it go from the right and to the bottom 1 0 0 0 0 line 2 0 1 0 0 0 line 3 0 0 1 0 0 line 4 0 0 0 1 0 line 5 0 0 0 0 1 line 6 but based on yours 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1
I guess if you switch the rows.. even though it looks kind of whacky, the rules aren't broken. that leading one is going to the bottom and right
1 0 0 0 0 0 1 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0
girl a 3x5 is 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
oh man thanks... sorry I was multitasking
lol I did a 5 x 5 my bad 1 0 0 0 0 0 1 0 0 0 0 0 0 0 1
there.. looks decent to me.
now lets write it in augmented matrix 1 0 0 0 0 line 3 0 1 0 0 0 line 4 0 0 0 0 1 line 5 looks consistent to me
3equations, 5variables, the rank of the matrix is at most 3, so, if it has 3 pivot columns, it is consistent. why not?
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