Question

am i correct??
1/cosθ+ tan^2θ/cosθ

1

1 + sinθ

cos^3θ <<

sec^3θ

Answer 1

no u r wrong

Answer 2

how come? then would it be 1+sinθ?

Answer 3

sec ^3(θ)

Answer 4

ok so in numerator we have 1+ tan^2(θ) = sec ^2(θ)
and in denominator we have cos (θ) => 1/ cos (θ) = sec (θ)
sec ^2(θ) * sec (θ) = sec ^3(θ)

Answer 5

ohhhhhh! i i got the numerator part but i didnt think of 1/cos(θ)= sec(θ) !! thanks a lot (:

Answer 6

Welcome :D