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A reaction is carried out for which the stoichiometry is A + 2B + 3C → D + 2E + F. In this reaction, 0.5 mole of A, 0.75 mole of B, and 1.0 mole of C are allowed to react. The yield of E is 0.2 mole. What is the percentage yield?
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First find the limiting reactant. You can then use stoichiometry to find the theoretical yield of E.
Percent yield = (actual yield / theoretical yield) x 100%
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