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Algebra Two Help: Given the function f(x) = log5(x + 1), find the value of f^−1(2).
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find the value of what?
inverse ?
inverse of the function f(x)=log5(x+1)
y = log5(x+1) you hav to write this in the exponential form from the function you see that the base 10 raised to the power of y is equal to 5(x+1) right?
The base is five. I'm not sure how to properly type out logs. The exponential form would be x=5^(x+1), right?
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oh, so it's log base 5 of (x+1)?
yes
right, then the base 5^y = x+1, in exponential form
subtracting 1 from both sides 5^y -1 = x we're looking for the inverse, then we swap x and y 5^x - 1 = y f^-1(2) = 5^(2) - 1
so 24
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yeah
Thank you so much1
no problem
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