Question

please walk me through the steps to figure this out: y^2+x^2=53 and y-x=5

Answer 1

u will end up with a quadratic eqn: ax^2 +bx + c = 0
do u know how to solve that?

Answer 2

uhm no, thats just the quadratic formula right?

Answer 3

yes...good that u know the quadratic formula....back to ur Q....
y-x=5 so by re-arranging, y=?

Answer 4

y=5+x

Answer 5

y^2(y-5)^2=53?

Answer 6

Sure...think u missed a "+" somewhere though :)

Expand (y-5)^2 and what will u get?

Answer 7

y^2-25?

Answer 8

oh yea i did! whoops, y^2+(y^2-25)=53

Answer 9

Nope (y+a)^2 = y^2 + 2ay + a^2....so try that plz?

Answer 10

what is a ?

Answer 11

scroll up see what u did...a in this case is -5 right?

Answer 12

(y-5)^2=y^2+2(-5)y+5^2 is that what you mean

Answer 13

yup yup n put that back into ur original eqn plz?

Answer 14

y^2+y^2+2(-5)y+5^2=53?

Answer 15

rearrange n regroup....I will do one part for you: +5^2-53 is -28

Answer 16

plz do the same for y^2 and y

Answer 17

i got it differently.
25+10x+2x^2=53

Answer 18

-28+10x+2x^2=0

Answer 19

Hmmmm what happens to the y? :P

so the eqn now looks like 2y^2 + 10y + (-28) = 0 right?