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OpenStudy (anonymous):
What is the formal charge of boron in the compound shown below? NaBF4
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OpenStudy (anonymous):
-1
OpenStudy (aaronq):
hmm i would argue that its +3. F= -1 x4 =-4 Na=+1 B must counter the -3 charge... so B is +3
OpenStudy (anonymous):
lol i just noticed i am wrong
OpenStudy (anonymous):
yeah sorry i only did borons on formal charge
OpenStudy (aaronq):
good try, though!
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OpenStudy (anonymous):
It was actually -1 . Thanks
OpenStudy (aaronq):
really? how?
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