Find the angle between the given vectors to the nearest tenth of a degree. u = <-5, -4>, v = <-4, -3> @agent0smith
a · b = |a| × |b| × cos(θ) | | means magnitude. a*b means dot product
i'm confused ...
Know how to find dot product? It's easy. a = <s, t> and b = <x, y> a·b = s*x + t*y
Determine whether the vectors u and v are parallel, orthogonal, or neither. u = <6, -2>, v = <8, 24>
We haven't finished the first question... and that one uses the same method.
a = <s, t> and b = <x, y> a·b = s*x + t*y do that for u = <-5, -4>, v = <-4, -3> u·v = ?
i got 1.8
@agent0smith
How? Multiply the x components together. Multiply the y components together. Add the two together u = <-5, -4>, v = <-4, -3> u·v = (-5)*(-4) + (-4)*(-3)
i got it as my final answer
for that 32
32 = |u| × |v| × cos(θ) where |u| = sqrt(5^2 + 4^2) |v| = sqrt(4^2 + 3^2) if you did something like this, and found theta you're right. I haven't checked the answer.
yeah i did that, do you think im right
Yes, 1.8 degrees is correct!
Yay c:
http://www.wolframalpha.com/input/?i=arccos%2832%2F%28sqrt%285%5E2+%2B+4%5E2%29*sqrt%284%5E2+%2B+3%5E2%29%29%29 there it is :)
u = <6, -2>, v = <8, 24> for this find u·v = ?
48,-48
@agent0smith
Dot product isn't a vector. you add the numbers.
Determine whether the vectors u and v are parallel, orthogonal, or neither. u = <6, -2>, v = <8, 24>
Find the indicated dot product. r = <9, -7, -8>, v = <3, 4, 7>, w = <6, -9, 7> v ⋅ w @agent0smith
Same as above. v = <3, 4, 7>, w = <6, -9, 7> v ⋅ w = multiply the x's, y's and z's
Same way you did it with the ones above, just this time you have two extra numbers to multiply.
18,-36,49?
Dot product isn't a vector, you add the numbers.
so 31
That's your answer :)
Express the complex number in trigonometric form. -3 + 3 square root of threei
Um, you'll have to find the r, which is the magnitude... sqrt( 3^2 + (3sqrt3)^2 ) and then find the angle. Tan theta = -3/(3sqrt3)
i got something completly off
...?
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