Will fan if helped! Evaluate the derivative of the given function at the given point y=x^2 - x @ (3,6)
True
Easy, use the formula: (a+h)-F(a) -------- h
And how would I incorporate it?
I really appreciate the help
plug in 6 in the a's
You are correct pickle
Have you been taught derivative yet? If yes, then find dy/dx and evaluate it at x = 3.
i mean plug it in the function.
so y = 3x - 1?
i mean 2x-1
y = x^2 - x dy/dx = 2x - 1 dy/dx at x = 3 is: 2 * 3 - 1 = 6 - 1 = 5
(a+h)^2-(a+h)- a
is that it ranga? what about ((a+h) - f(a))/h ?
that equation confuses me
Ok, are you confused about what you post, or if you are correct?
just plug in (a+h) in the x's and then do (minus a) at the end of that equation because there's is - f(a) at the end of the formula
If you have not been taught derivatives yet, then you will have to do it the other way and evaluate the limit. But if you have been taught derivatives this is the easier way.
ahh I see, thanks
You are welcome.
tell me what you found
y= 3x -1 x = 3 y= 3(2) - 1 y = 5
Good job :)
ok, it seemed a lot mroe complicated then it was since the equations seemed kind of daunting.
but thanks
The secret is to follow the formulas
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