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Physics 11 Online
OpenStudy (anonymous):

A 55.0-g Super Ball traveling at 29.0 m/s bounces off a brick wall and rebounds at 19.5 m/s. A high-speed camera records this event. If the ball is in contact with the wall for 3.40 ms, what is the magnitude of the average acceleration of the ball during this time interval?

OpenStudy (anonymous):

do you know anything about impulse?

OpenStudy (anonymous):

i literaly just started physics

OpenStudy (anonymous):

look in your book and give me an attempt at a problem with impulse let me see where your at

OpenStudy (anonymous):

the first page impulse is started is pg 253. we have read to only 30. but this what it says...

OpenStudy (anonymous):

delta(t) = tf-ti

OpenStudy (anonymous):

and also vetors

OpenStudy (anonymous):

oh you can just do it this way

OpenStudy (anonymous):

i think it is vi-vf/t maybe the t is squared to. ill have to look in my old book real fast. i donno where it is.

OpenStudy (raffle_snaffle):

impluse=mv

OpenStudy (anonymous):

im just talking about, the magnitude of the acceleration. i was getting ahead of him

OpenStudy (anonymous):

can just take the initial - the final velocity/2 to get acceleration

OpenStudy (anonymous):

ill try that

OpenStudy (raffle_snaffle):

Douglas after your done here can you please help me with my phy question referring to work?

OpenStudy (anonymous):

Yes, impulse is force x time, but not needed here. Acceleration is change in velocity divided by time: acc = (29 -(-19.5))/ (3.4x10^-3) = (48.5/3.4) x 10^3 (

OpenStudy (anonymous):

ya, i donno why i put 2 the second time i typed that. lol

OpenStudy (anonymous):

i got .0034

OpenStudy (raffle_snaffle):

so we done here?

OpenStudy (anonymous):

? for the numerator? or the answer

OpenStudy (anonymous):

or is it positive ^3?

OpenStudy (anonymous):

then it would be 14264.7

OpenStudy (anonymous):

that is what i got.

OpenStudy (anonymous):

i submitted it and it was wrong :(

OpenStudy (anonymous):

do you have to use sig figs?

OpenStudy (anonymous):

this is really hard!

OpenStudy (anonymous):

sig figs?

OpenStudy (raffle_snaffle):

ha really head. you should go see my question

OpenStudy (anonymous):

nevermind then lol is there a rounding rule on the problem. i looked at your question raffle. i am not as smart as you lol.

OpenStudy (raffle_snaffle):

i am not very smart either... that is why i am asking for your help bro

OpenStudy (anonymous):

im just starting give me a little break! lol

OpenStudy (anonymous):

its fine man, its hard when i dont know what you know.

OpenStudy (raffle_snaffle):

Haha josh just giving you ahard time=P

OpenStudy (anonymous):

i never liked word problems in math and then i got to this class.... lol

OpenStudy (anonymous):

i know someone that could help, but he isnt on this site. and all physics is word problems, get used to it lol.

OpenStudy (anonymous):

calc1-2 passed too

OpenStudy (anonymous):

isnt it the least bit interesting knowing about stuff in the universe, or around you that is moving or sitting still, what is really going on

OpenStudy (anonymous):

i think the universe is very interesting in of it self

OpenStudy (anonymous):

ive taken astronomy classes just for fun

OpenStudy (anonymous):

if you havent figured this problem out before i get back ill see what i can do to get you the right answer. i bet your not rounding to the right decimel place.

OpenStudy (raffle_snaffle):

nice, wish i had time to take some astronomy classes for fun

OpenStudy (anonymous):

That answer should have been close to a= 15,000 m/s^2.

OpenStudy (anonymous):

it was one of those "required" classes

OpenStudy (anonymous):

it was close to that 142xx im thinking he is inputting into masteringphysics or something that wants it to the .xxx decimal place.

OpenStudy (anonymous):

i bet. kind of silly to have online questions like this. but what do i know

OpenStudy (raffle_snaffle):

Why didn't the acc=deltaV/delta t work?

OpenStudy (anonymous):

thanks for your help guys.

OpenStudy (raffle_snaffle):

you good?

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