how Could I find the two missing angle measures if I know some of the side lengths of a right triangle?
if u got 2 sides of a right-angled triangle, then u can find the third one by c^2=a^2+b^2 then with all sides known, u can solve for the angles.
im confused. How would that work????
which sides are given in the right-angled triangle?
Im looking for angles and need to solve with lengths. and I have no idea. there isnt a certain problem
drawing tool is down in OS :( but u know in a right-angled triangle, c^2=a^2+b^2 where c is the longest side right?
yeah. the hypotenuse?
yup yup....so if u get any 2 side lengths, u can solve for the missing one ok?
yeah but I thought if i were looking for an angle i could solve with sides?
yup...u can then either the trig ratios such as sinA=a/c or cosA=b/c to find the angles.
u can then USE either...
what do I do after I have what I have : cos(x degrees) = adjacent/hypotenuse cos(x degrees) = 23/25 cos(x degrees) = 0.92
then u can use arcos or cos^-1 or inv.cos on ur calculator to find the angle
this doesnt look right.. ≈0.402715842
hehehe thats because ur calculator is set to "radian" - look for a button that said "degree" it should come out to about 23 deg.
ok I was just using a bad online calculator. Thank you so much!!!!
welcome :)
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