Question

Please show all steps! Will give a medal and become a fan of best answer. :)

What is the sum? State any restrictions on the variable.
3x/x^2-9 + 3/x^2-6x+9

Answer 1

are those suppose to be division signs

Answer 2

It's an addition problem between two fractions. Like this: 3x over x^2-9 plus 3 over x^2-6x+9

Answer 3

I would draw it out but for some reason the draw and equation parts aren't working on my computer and I can't see it when someone uses them. Hopefully you can see this pic.

Answer 4

so we are adding them?

Answer 5

I guess I don't really understand the question. @lonnie455rich

Answer 6

Yeah. It asks for the sum, and says to state any restrictions on the variable.

Answer 7

I think my first step would be to factor but I'm not too good with that..

Answer 8

well I don't want to lead you in the wrong direction. Let me find someone who can help you with this better than I can. Lol

Answer 9

@tkhunny

Answer 10

Lol okay. :)

Answer 11

get the least common denominator

Answer 12

first, factor the denominators

Answer 13

3x/(x+3)(x-3) + 3(x-3)^2 ?

Answer 14

yeahhhhhh go loniie!!!

Answer 15

the second part would be 3/(x-3)^2 but ya you get it. now get the least common denominator. i think raffle was thinking about summations in calculus or something lol

Answer 16

the restriction on the variable would be what would make the denominators = to zero.

Answer 17

so rest would be 3 or -3

Answer 18

Lol thats okay @raffle_snaffle! And so would it be (x-3) right?

Answer 19

the lcd would be (x+3)(x-3)(x-3)

Answer 20

so on the left one you multiply numerator and denominator by (x-3) and the one on the right you would multiply (x+3) the same way

Answer 21

Okay now I'm a little lost..

Answer 22

uhh let me draw it on paint real fast.

Answer 23

So that would make it (3x/(x+3)) + 3 right? Cause you have to cancel them?

Answer 24

Okay lol.

Answer 25

lets see if this makes things clear

Answer 26

Ooo okay. That makes sense. Then do I cancel things out?

Answer 27

hm. no. you add the numerators.

Answer 28

Would it be 6x(x-3)(x+3)? The numerator

Answer 29

if you canceled them you would undo what you did finding the least common denominator.
i just did
3x(x-3)+3(x+3) then all that over the lcd you cant add a constant and a variable term

Answer 30

distribute the 3x to the x-3 then distribute the 3 to the x+3

Answer 31

Oh okay. 3x^2-3 for the first part? Then 3x+9 for the second numerator?

Answer 32

Sorry I'm making you go thru all this :/ lol

Answer 33

no you have to multiply 3x to 3 as well

Answer 34

distribute it.

Answer 35

its all good.

Answer 36

your right on the second part on 3x+9

Answer 37

do i get a medal for finding someone who can help you?

Answer 38

3x^2-9x?

Answer 39

yes that will be your first term. add that to your second term and you have your numerator.

Answer 40

raffle. lol. that pic

Answer 41

i was kind of partial to the magnetic field pic

Answer 42

How can I give you both a medal raffle? I will if I figure it out! And okay, hang on let me try to add them.

Answer 43

6x^3+x, cause -9 + 9 would just be 0

Answer 44

the -9 has an x term so you cant do that.
3x^2-9x+3x+9. do this operation

Answer 45

3x^2-6x+9

Answer 46

all over your denominator. and you can factor a 3 out of that if you need giving you 3(x^2-2x+3)

Answer 47

Do I need to distribute the denominator too?

Answer 48

Oh wait.. nevermind. Lol

Answer 49

At first I thought the last thing you posted was the denominator.

Answer 50

lol you're getting it. i just factored a 3 out of the numerator. like i say in my profile quote. im not the best at explaining things, i try though.

Answer 51

Lol well I thank you for having the patience to help me!! Math sucks lol.

Answer 52

So 3(x^2-2x+3)/(x+3)(x-3)^2 is how it's supposed to be written, right?

Answer 53

yes that is correct, math doesnt suck, its just hard for some people so they dont like it. math people have the same problems with english, history, and any other class requiring rote memorization.

Answer 54

Is that the end of the problem? And yeah that's true. It is hard for me to understand. It just doesn't make sense. I have all good grades and math is the only thing holding me back from being able to graduate early. :/

Answer 55

just practice, that's all it takes. if you get frustrated. take a break you will get it.

Answer 56

Thanks for all your help, :) I really appreciate it. And thanks @raffle_snaffle!

Answer 57

no problem, good luck