Question

Hydrogen peroxide, H2O2, is a colorless liquid whose solutions are used as a bleach and an antiseptic. H2O2 can be prepared in a process whose overall change is

H2(g) + O2(g) → H2O2(ℓ)

Calculate the enthalpy change using the following data:

2H2O2(ℓ) → 2H2O(ℓ) + O2(g); ∆H = -196.0 kJ

H2(g) + 1/2O2(g) → H2O(l ); ∆H = -285.8 kJ

Answer 1

I thought it would be (196.0)/2 + (-285.8)

Answer 2

-196*

Answer 3

I think it is (196.0kj/2)+(-285.8kj)

Answer 4

196 or -196?

Answer 5

196 becayse you need to reverse the first reaction so the H

Answer 6

becomes positive

Answer 7

Yup @rzrhdes ur first one was correct

Answer 8

the first answer is correct. Flip the first reaction backwards and cut it in half, so the \(\Delta H\) becomes positive and halved. Then add the two reactions together