GEOMETRY HELP PLEASE
@annas
well im gonna tank a wild guess ad say that since AD is near the same length as AB Ab would be 28.6 but i didnt do any math and that could be totally wrong so id wait for a second opinion from some one else.
take****
there is formula for finding the length of a scalene triangle i.e. c^2 = a^2 + b^2 - 2*a*b*cos(90) I dont think this formula will work here
just popping back i dont remember the formals for most things but i had to wonder if i was right? @annas
thats what I am thinking, well just a moment lemme get it checked
AB / BC = BD / CD AB = (BD/CD) * BC AB = (12.2/7.7)*2.2 = 3.48 ugh..
Dude Idk. Like this problems picture throws me off, it looks isosceles, but.
Would BC = the angle BAC?
This problem is missing something. I can draw an infinite number of triangles with what is given. Is for example Is AC the bisector of DAB? if this known, then it would be solvable
I would let others respond and solve it if they can. @experimentX , @satellite73 @ganeshie8
okie sir :)
assuming what prof said ... the answer is http://www.wolframalpha.com/input/?i=N%5B4.5*16.7%2F7.7%2C+2%5D use cosine law ... it is quadratic in AC. assume that there exists only one solution for AC. then eliminate the cosine of angle ... you will get AB = BC*AD/CD
assuming what prof said ... the answer is http://www.wolframalpha.com/input/?i=N%5B4.5*16.7%2F7.7%2C+2%5D here is rough sketch of proof. use cosine law ... it is quadratic in AC. assume that there exists only one solution for AC. for that determinant has to be zero. then eliminate the cosine of angle ... you will get AB = BC*AD/CD
Join our real-time social learning platform and learn together with your friends!