Question

.

Answer 1

do u have any idea on this @adrianajones

Answer 2

ur right now u have to find which one is limiting reagent

Answer 3

convert 13.4 g of aluminum chloride in to moles
and 10 g of sodium hydroxide moles using respective molar mass

Answer 4

yup :) and that of NaOH ?

Answer 5

AlCl3 + 3 NaOH -> Al(OH)3 + 3 NaCl
according to the equation u have balanced 1 mole of AlCl3 needs three moles of the NAOH right

Answer 6

so now for 0.1 moles of AlCl3 u need how much of NaOH ?

Answer 7

mean it requires 0.3 mole of NAOH but they have given u only 0.25 moles of NAOH right ?

Answer 8

lol nope

Answer 9

0.1 mole of AlCL3 requires 0.3 moles of NAOH
according to this equation
AlCl3 + 3 NaOH -> Al(OH)3 + 3 NaCl

but what they have givn u in problem is
0.1 mole so AlCL3 and 0.25 mole so NaOH
so u have less NaOH than required ? right

Answer 10

so which is less in quantity is limiting reagent ?

Answer 11

yup :)

Answer 12

molar mass of Aluminium hydroxide ?

Answer 13

3 mole so NaOH produces = 78 .0036 g of Al(OH)3
0.25 moles of NaOH produces = ?

Answer 14

0.25*78 /3

Answer 15

lol idk that if u have done properly :)

Answer 16

lol 6.5 is right

Answer 17

no idea................... sorry THINK 6.5 IS THE CORRECT ANSWER .