Question

Solve: 4^2x = 32^1/2

Answer 1

is that (32^1)/2 or 32^1/2?

Answer 2

it is 32^1/2 (32 exponent 1/2)

Answer 3

i got x = 1 over 2 square root 2

Answer 4

Hmm, its not one of my choices. But i did use wolfram alpha nd it got the same.

Answer 5

what are your choices?

Answer 6

2/9, 1/2, 3/4, 5/8

Answer 7

4^(2x)=(32)^(1/2)

Answer 8

(4^((2)^x))=32^(1/2)

Answer 9

(4^((2)^x))=32^(1/2)
16^x=32^(1/2)

Answer 10

best is take log on both sides !

Answer 11

So, log16^x = log32^1/2

Answer 12

you could write 4 and 2^2
and 32 as 2^5

Answer 13

yes

Answer 14

x*log 16 =1/2 log(32)

Answer 15

x=0.5*(log(32)/log(16))

Answer 16

in other words
4^(2x) = 32^½

with 4= 2^2 and 32= 2^5
(2^2)^(2x) = (2^5)^½

which is the same as
2^(4x) = 2^(5/2)

now equate exponents (you have the same base)

Answer 17

yes ,phi method is also easy.

Answer 18

then your left with 4x = 5/2
now solve for x by dividing both sides by 4
and get x = 5/8

Answer 19

:)

Answer 20

yes ! x=5/8

Answer 21

:) yay!

Answer 22

:) (:

Answer 23

:) thanks @CGGURUMANJUNATH and @phi its starting to make more sense

Answer 24

if you are really enthusiastic, try doing the problem CG's way.

Answer 25

I think that is to hard for me lol :)

Answer 26

have u been taught about logarithms ?

Answer 27

one can solve this problems by 2 methods !
1. exponents
2. logarithms

Answer 28

Yes i have but i dont quite understand it all. some are easy and others are difficult.