Question

A helicopter hovers 40 ft above the ground. Then the helicopter climbs at a rate of 21 ft/s. Write a rule that represents the helicopter’s height, h, above the ground as a function of time, t. what is the helicopter’s height after 45 s?

Answer 1

Help?

Answer 2

you need to write a function h(t) that represents the height. at t = 0, the helicopter is hovering at height t0 = 40

after that, the helicopter is at t0 + rc*t where rc is the rate of climb in ft/s and t is the time in seconds

complete that formula and evaluate it with t = 45 s to find the height after 45 seconds of climbing

Answer 3

So whats the answer?

Answer 4

??

Answer 5

I gave you the information you need to figure out the answer. what have you got so far?

Answer 6

I dont get it..

Answer 7

..

Answer 8

okay, the helicopter is hovering initially, right? what height is it at?

Answer 9

40

Answer 10

okay. after 1 second of climbing, what is the height of the helicopter, if it climbs at 21 ft/s?

Answer 11

61

Answer 12

how about after 2 seconds?

Answer 13

82

Answer 14

how about after 10 seconds?

Answer 15

250

Answer 16

Right?

Answer 17

that's right. how did you figure it out?

Answer 18

did you do 40 + 21 + 21 + 21 + ... = 250, or did you do 40 + 21*10 = 250?
I hope you did the latter. that's the formula: initial height + rate of climb * time
evaluate it for time = 45 seconds and you have the answer to the second part