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Mathematics 8 Online
OpenStudy (anonymous):

Solve for both exact form and decimal form (rounded to 3 decimal places!) 1=12tan(3x+5)-5 so would it be add 5 to both sides? 6=12tan(3x+5) divide by 12 ? 1/2=tan(3x+5) ?? is that right so far? :) thanks!!

OpenStudy (phi):

yes. it's the same problem with slightly different numbers.

OpenStudy (agent0smith):

Keep going.

OpenStudy (anonymous):

okay, so you let t=tan(3x+5) ? is that it? :/ this is where i'm confused again :(

OpenStudy (agent0smith):

Do it like last time. Inverse tan of 1/2

OpenStudy (anonymous):

okay:) umm tan^-1(1/2) -5+k*pi/3 ?

OpenStudy (phi):

if you put parens in to show all of it is divided by 3

OpenStudy (anonymous):

oh so (tan^-1(1/2) -5+k*pi)/3 ?

OpenStudy (anonymous):

and that would be the exact form? :)

OpenStudy (phi):

yes. Once you use a calculator to evaluate the inverse tan, you end up with a decimal number that (though it has lots of digits) is still rounded... hence it will be inexact once you change to decimals

OpenStudy (anonymous):

(tan^-1(1/2) -5+k*pi)/3 = -1.512 ? so ^^=exact form and ^^=decimal form? :)

OpenStudy (agent0smith):

(tan^-1(1/2) -5+k*pi)/3 and (tan^-1(1/2) -5)/3 + kpi/3 ^do that part in brackets on a calc, for decimal form.

OpenStudy (anonymous):

so -1.512 + kpi/3 ? or is it (-4.536 + kip)/3 ?

OpenStudy (phi):

they are the same thing... but you computer may just be expecting -1.512 (ask you teacher)

OpenStudy (anonymous):

okay :) i will :) awesome!! yay thank you both!!! :)

OpenStudy (anonymous):

okay :) i will :) awesome!! yay thank you both!!! :)

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