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Mathematics 7 Online
OpenStudy (anonymous):

What is a possible solution to the graph attached inside? **answer choices attached inside as well :) not sure if i'm right though :/

OpenStudy (anonymous):

graph!

OpenStudy (anonymous):

answer choices A,B,C,D,E from top to bottom :) I've narrowed it down to A and B... but i'm thinking that it's B since the parabola open upwards? not sure though... what do y'all think? :)

OpenStudy (ybarrap):

The easiest way to solve this problem is to look and see where the function crosses the x-axis. Where are the 3 places where this happens?

OpenStudy (anonymous):

crosses at x=-4, 3 and 5... so then it would make it (x+4)(x-3)(x-5) when set to 0 right?

OpenStudy (ybarrap):

yes

OpenStudy (anonymous):

okay :) so how do you figure out if it's -k or k? not sure if my reasoning is correct haha :P

OpenStudy (ybarrap):

Now if x gets large, what happens to the function?

jimthompson5910 (jim_thompson5910):

Start from the left most point on the graph. Then travel along the curve until you hit the right most point. From the beginning point to the end point, have you gone up or gone down?

OpenStudy (anonymous):

ohh so would it be negative? since it keeps moving downward? and @ybarrap when x gets larger, the function decreases?

OpenStudy (anonymous):

@jim_thompson5910 down?

jimthompson5910 (jim_thompson5910):

yep, so the the leading coefficient must be negative

OpenStudy (anonymous):

ohh okay :) so it becomes g(x)= -k (x+4)(x-3)(x-5) ? :)

OpenStudy (ybarrap):

The behavior for large x is determined by the highest power coefficients. So, we see that at some point x will be multiplied 3 times, giving us something times x^3. Now since we know that the function will go negative with positive x, we know something about the sign of k.

OpenStudy (anonymous):

okay, awesome :) hehe thanks you guys!! :)

OpenStudy (ybarrap):

That's right. You did well. Thank YOU for working this out.

OpenStudy (anonymous):

hahaa thanks @ybarrap :)

OpenStudy (anonymous):

hahaa thanks @ybarrap :)

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