Question

For the function f(x)= (3x-3)/(2x+7), find...

the horizontal asymptote... y=____

and the vertical asymptote... x=_____

**for horizontal, the exponents are equal right? so 3/2 is the horizontal asymptote?

and for the vertical, i have to factor it out right? but i feel like it's not factorable?

what do you think? :) thanks!!

Answer 1

the horizontal asymptote is correct

Answer 2

you are correct on the horizontal

Answer 3

ooh yay! :)

Answer 4

hurray!! XD

Answer 5

to find the vertical asymptote, set the denominator equal to zero and solve for x

Answer 6

haha wooowoo :P

except I'm lost on the vertical one lol so woowoo-woo=woo :P

Answer 7

ohhh okay

so 2x+7=0

-7 -7

2x=7

x=7/2 ?

Answer 8

To find the vertical, set the denominator equal to zero and solve.

Answer 9

this is because you cannot divide by zero

values that cause division by zero errors yield vertical asymptotes

Answer 10

2x+7 = 0 doesn't lead to 2x = 7

Answer 11

ohh okay :)

oops... my bad!

2x= -7

x= -7/2 ?

Answer 12

much better

Answer 13

haha okay :)

wait so if it's factorable, there would be two vertical asymptotes?

Answer 14

and if it's not, just set it equal to 0 and solve for x?

Answer 15

yes, assuming nothing cancels

Answer 16

okay :) great!! Thank you!! :)

Answer 17

you're welcome

Answer 18

okay :) great!! Thank you!! :)