Question

Help with this problem?

Answer 1

http://prntscr.com/2nib0k

Answer 2

shoot

Answer 3

-x from both sides

Answer 4

x=2?

Answer 5

@jim_thompson5910

Answer 6

Solution of this problem should consist of 2 steps: (1) find possible x-values and (2) verify that each such x value actually is a solution. It's very possible that you'll get two distinct x values and that only one is actually a solution; the other would then be dubbed 'extraneous root."

Answer 7

Square both sides of Sqrt(3x) = Sqrt(x+6).

then 3x = x+6. (In this case there's only one possible root, and that root is x=3.)
substitute x=3 into the orginal equation and decide whther or not that equation is now true.

Answer 8

I dont get it

Answer 9

You square both sides of the equation getting 3x=x+6
Then, you solve for x. So subtract x from the (x+6) side which gets you 2x=6.
From there, divide 6 by 2 to get x.

Answer 10

how would i do this one http://prntscr.com/2nigfr

Answer 11

Okay, so for this one, you have to distribute the 1/2
So if I distribute 1/2 to the (7x+6) part, I get (7/2x + 3).
Then, I distribute the 1/2 to the (9+4x) part getting (9/2 + 2x)
So put those parts together to get (7/2x + 3) - (9/2 + 2x) = 0
I'm going to distribute the negative sign in front of (9/2 + 2x) to get the entire equation of
7/2x + 3 -9/2 -2x = 0
Then, I combine like terms getting 1.5x - 1.5 = 0
I add the 1.5 over to the 0 getting 1.5x = 1.5
Then, divide 1.5 by 1.5 getting x = 1.

Answer 12

i got x=1 too but i did it differently

Answer 13

I squared the 2 radicals and got 7x+6=9+4x then I combined the like terms and got 3x-3=0 then i subtraced the 3 from both sides which will give you 3x=3 and i divided and got 1

Answer 14

Oh! The 1/2 were exponents. I thought they were multiplying. Yeah, you're definitely right. You did it correctly.

Answer 15

By all means move the 2nd term of the left side of this equation to the right side. From that point on, solve for x in the same manner as I (or mwin) suggested earlier.

Answer 16

Yep, that 1/2 is an exponent; here it denotes a Square Root.

Answer 17

im so confused