diving radicals help

Question

the_fizicx99 · Answer

Question?

anonymous · Answer

∛(27x^9 y^3 )/∛(8x^6 y^6 )

anonymous · Answer

@tHe_FiZiCx99

the_fizicx99 · Answer

Gimmie a sec im busy atm

anonymous · Answer

so then you cant help me?

the_fizicx99 · Answer

I can, hold on a sec

the_fizicx99 · Answer

Might need to work it out on paper

anonymous · Answer

ok i just really want to understand it. cause im having trouble with it right now

the_fizicx99 · Answer

Ok, I got 3 3√x^9 y^3 / 2 3√x^6 y^6

anonymous · Answer

whaat? that looks complicated

the_fizicx99 · Answer

Um what grade are you in?

anonymous · Answer

why?

the_fizicx99 · Answer

Because that's what its suppose to look like.. it'll look complicated if your in algebra I.

the_fizicx99 · Answer

That's geometry ._.

anonymous · Answer

can you explain the steps please?

the_fizicx99 · Answer

This is going to look like crap without latex D: too messy

i can make an attempt though

anonymous · Answer

you can write it in equation

the_fizicx99 · Answer

The equation tab is latex xD

anonymous · Answer

well can you explain it then??????

the_fizicx99 · Answer

I'll try ._.

the_fizicx99 · Answer

Or make a decent attempt anyway.

agent0smith · Answer

∛(27x^9 y^3 )/∛(8x^6 y^6 )
this will be hard to read w/o latex...

∛(3^3 (x^3)^3 y^3 )/∛( (2^3) (x^2)^3 (y^2)^3 )

the_fizicx99 · Answer

._______________________. ^

-killed my thunder-

the_fizicx99 · Answer

That looks messier than mine ._.

agent0smith · Answer

^put everything so it's to the power of 3. like 27 is 3^3. x^9 is (x^3)^3

anonymous · Answer

im still so confused omgg

the_fizicx99 · Answer

Dat factoring tho ._. you lost me in the last part, i geddit :3

anonymous · Answer

@agent0smith can you help me get it please?

agent0smith · Answer

∛(3^3 (x^3)^3 y^3 )/∛( (2^3) (x^2)^3 (y^2)^3 )

the reason to put it all the power of 3 is because it's a cube root.
because
∛a^3 = a

so...

∛(3^3 (x^3)^3 y^3 )/∛( (2^3) (x^2)^3 (y^2)^3 )

3 x^3 y/2 x^2 y^2

agent0smith · Answer

Now you still have to simplify that, just by dividing it all.

anonymous · Answer

thats alot!!!!

agent0smith · Answer

er what?

3 x^3 y/2 x^2 y^2 = 

3x/2y

anonymous · Answer

on ∛(3^3 (x^3)^3 y^3 )/∛( (2^3) (x^2)^3 (y^2)^3 )

anonymous · Answer

i hate math ugh

agent0smith · Answer

You're cube rooting everything. That means 3^3 becomes 3. (x^3)^3 becomes x^3, y^3 becomes y, etc.

anonymous · Answer

so the final answer will be 3x/2y right?

anonymous · Answer

@agent0smith ^

agent0smith · Answer

Correct :) it would be MUCH easier to follow if the equation editor worked, btw.

anonymous · Answer

i know, thanks anyway:)