Can somebody show me how to work this out? x^3-2x^2+3x+10=0
So you need to find the roots?
Yes ma'am @raechelvictoria
So far I found the factors of 10 and x^3. Am I headed in the right direction?
Yes. Then substitute those values into the equation until you the equation will equal to zerio (remainder theorem)
I couldn't find a number that balanced it out. Maybe I messed up on the math. I will try again.
Hmm it turns out the real root is x = -1.3387. Are you sure you posted the equation correctly?
I'm dumb I posted the wrong thing. Here is the original equation: q(x)=x^4-4x^3+x^2+16x-20. That other equation was after synth div
When 2 was under the bracket. Where do I go from there?
Oh so you already found 2 to be a root? That looks correct. Maybe you made a boo boo when you did the division, lemme check.
Synthetic Division is giving me: x^3 - 2x^2 `- 3x` + 10 = 0 See the minus on the 3x? Maybe you made a small error right there.
Indeed. Thank you for catching that. What next?
So you took the factors of your constant and divided them by the factors of your leading coefficient. That gave you possible rational roots. You'll need to check them again :c grr Hint hint: Check 2 and -2 again. One of those should work out.
I'm confused what you mean I need to check them again?
I see what you mean @zepdrix -2 did work so now I'm going to use the quad formula. Thanks for all the help!
I ended up with roots of -2,2,2+i, and 2-i
Ah good job! :)
This is another one I'm going to work on g(x)=x^6-1. So would I do the same steps?
For g(x) we can write it as the `difference of squares`. x^6 = (x^3)^2 1 = 1^2 x^6 - 1 = (x^3)^2 - 1^2 Do you remember how to factor the difference of squares? They break down into `conjugates`.
No I don't remember how to do that.
Difference of squares break down into factors like this: a^2 - b^2 = (a-b)(a+b) So in our problem, it would factor down to: (x^3 - 1)(x^3 + 1)
I ended up doing syth division, but that other way is quicker.
Oh synthetic worked on this one? cool
So here are my final roots 1,-1, -1+-iSqrt(3)/2, and 1+-isqrt(3)/2. Does this look right?
Ya that's what I'm getting also.
Alright, thanks again for helping me out!
Refer to the Mathematica calculation.
Thank you both @robtobey @zepdrix
Your welcome. You might be interested in the following video. http://www.ted.com/talks/conrad_wolfram_teaching_kids_real_math_with_computers.html
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