What's the logarithmic equation 2=log(3x+4)
Gimme one sec, I got somethin for ya
All logs without a base written in are base 10, and logs are like the inverses of exponents
Are you able to solve the problem once it's in exponential form?
Thank you so much for that, @zepdrix! I usually have trouble when it comes to putting it in exponential form and then solving. However, I'll see what I can do. 10^2=3x+4 so 100=3x+4 subtract 4 from 100 and 4 96=3x divide by three on both sides. So, my answer would be 32?
Could either of you maybe explain to me how we would convert 5=log3 (x^2+18) or e^x e^(x+1)=1 into an exponential equation and then solve?
Try to draw the arrows like I was doing before! :O So the base 3 points to the 5, then the 5 points to the x^2+18. It's like a spiral that goes around. So the exponential form is: 3^5 = x^2+18
So the other equation: e^x * e^(x+1) = 1 This one is uhhhhh a little tricky. So we'll apply a rule of exponents: When we multiply terms of similar bases, we ADD the exponents. So our left side becomes: e^(x+(x+1)) = 1 We can then rewrite 1 in terms of the exponential of base e. e^0 = 1 let's write our right side like this. e^(x+x+1) = e^0
The bases are the same, which means the exponents have to also be equal. Set them equal to one another. x+x+1 = 0 Then it's pretty straight forward solving for x from there.
Yes! Thank you so much for all your help!! Just to make sure, the final answer to that problem is x= -1/2, right? @zepdrix
I'd like to present a different point of view: As samarasamara has pointed out, All logs without a base written in are base 10, and logs are like the inverses of exponents These two facts are instrumental in solving this present problem. Given 2 = log (3x+4) and the equation 10 = 10, Let 2 be the exponent of the left 10 and let log(3x+4) be the exponent of the right 10. 2 This reduces to 10 = 3x+4, or 100=3x+4, or 3x=96, or x=?? that's the solution.
-1/2? Ya looks good!
zepdrix: perhaps we'd better each check our respective "answers" in the original equation.
log (3[32]+4) = log 100 = log 10^ 2 = 2. log (3[-1/2]+4) = log (1/2) = log 1 - log 2 = 0 - log 2, or approx. -0.693.
Join our real-time social learning platform and learn together with your friends!