Question

evaluate the sum (6 + 2k)^2 + (k + 3) / (k(k + 4))
lower limit: k=-3
upper limit: n-3
starting with k=0

Answer 1

do you know the theories?

Answer 2

yeah but for some reason i cant apply them to this question

Answer 3

Replace k by k - 3
can you put parantheses to let me understand which is the numerator and denominator ?

Answer 4

ok i fixed it. k + 3 is the numerator and k(k +4) is the denominator

Answer 5

great as i said, replace k by k - 3 so sum goes from 0 to n
now we have
sum over 4k^2 + 1/(k) - 1/(k(k+4)) = 4k^2 + 1/k + [1/k - 1/(k+4)]/4

now you plug in the formulas

Answer 6

@elsanna Was k replaced by (k-3) in the second part of the original summation?