please help, What is the average binding energy per nucleon for a C-12 nucleus with a mass defect of 0.0993 amu? (1 amu= 1.66 x 10-27 kg; 1 J = 1 kg m2/s2)
Answer

1.48 x 10-11 J

1.24 x 10-12 J

4.12 x 10-21 J

8.94 x 1015 J

Question

please help, What is the average binding energy per nucleon for a C-12 nucleus with a mass defect of 0.0993 amu? (1 amu= 1.66 x 10-27 kg; 1 J = 1 kg m2/s2)
Answer
		
1.48 x 10-11 J
		
1.24 x 10-12 J
		
4.12 x 10-21 J
		
8.94 x 1015 J

wolfe8 · Answer

Check this out: http://openstudy.com/study#/updates/51b17fcde4b06ee3ee277632

anonymous · Answer

ok

anonymous · Answer

I saw that actually. But, I don't understand. I was hoping I could find a simpler  explanation??

wolfe8 · Answer

First you change the mass from amu to kg

wolfe8 · Answer

1) Convert mass from amu to kg
2) Use E=mc^2

wolfe8 · Answer

3) Divide by number of nucleon

anonymous · Answer

Ok. Here this shows  0.0624 as the amu, is that what I would use with E=mc2?

wolfe8 · Answer

No you have to change it to kg first, as I said. The post I linked showed you how to do that.

anonymous · Answer

1.03617629 × 10^-28 kg, does that look right?

wolfe8 · Answer

Wait. Where did you get 0.0624 amu? The questions says 0.0993 amu

anonymous · Answer

Sorry, I got all of my equations on same page.

anonymous · Answer

1.64891515 × 10-28 kilograms this would be conversion for0.0993

anonymous · Answer

1.64891515 × 10^-28 kilograms

wolfe8 · Answer

Yeah that looks right although our decimal points are different. Now you can use the formula E=mc^2