Question

I am checking my work:

The actual measured mass of a beryllium-9 atom is 9.012182 atomic mass units (amu) and the expected mass is calculated to be 9.072429 amu. Therefore, the mass defect for a beryllium-9 nucleus is 0.0624 amu. (1 amu= 1.66X10-27 kg) How much energy will this reaction provide?
Answer

3.12 x 10-20 kg m2/s2

9.36 x 10-12 kg m2/s2

3.46 x 10-36 kg m2/s2

1.11 x 10-11 kg m2/s2

I believe it is:
9.36 x 10-12 kg m2/s2?

Answer 1

∆E = ∆mc^2

∆m = (9.072429-9.012182) [amu]
= 0.060247 [amu]
= 0.060247 [amu] * 1.66*10^-27 [kg/amu]
= 1.0001002e-28 [kg]

c = 2.997925*10^8 [m/s]

∆E = ∆mc^2
= 1.0001002e-28 [kg] * (2.997925*10^8 [m/s])^2
= 8.988452e-12 [kg m^2/s^2]
= 8.99e-12 [J]

Answer 2

close enough

Answer 3

Thanks so much UnkleRhaukus!!!