Find the polar coordinates of the point whose rectangular coordinates are (-3,-3).

a.) (-3 sqrt(2),5 pi /4)
b.) (3 sqrt(2),pi /4)
c.) (18,pi /4)
d.) (3 sqrt(2),5 pi /4)

Question

Find the polar coordinates of the point whose rectangular coordinates are (-3,-3).
 	
a.) (-3 sqrt(2),5 pi /4)
b.) (3 sqrt(2),pi /4)
c.) (18,pi /4)
d.) (3 sqrt(2),5 pi /4)

superdavesuper · Answer

to convert (x,y) to (r, theata) use the eqns: x=r*sin(theata) and y=r*cos(theata)

anonymous · Answer

You need to find r and $ \theta$. In which quadrant is (-3,-3} and what is the distance to the origin?

anonymous · Answer

-3?

anonymous · Answer

How do you find the distance from (0,0) to (-3,-3)?
$$
r=\sqrt{( -3-0)^2+(-3-0)^2}=\sqrt{18}=\sqrt{ 9(2)}= 3 \sqrt 2

$$

anonymous · Answer

We have to chose between b and d,  using the angle $\theta$
Can you do that?

anonymous · Answer

distance is 3 sqrt(2) and angle is pi/4.

anonymous · Answer

The angle pi/4 will put you in the first quadrant and your point is in the third quadrant

anonymous · Answer

r is 3sqrt(2) and theata is 5pi/4.....d right?

anonymous · Answer

Yes

anonymous · Answer

yay! thanks so much.

anonymous · Answer

YW