Question

Which relationship shows a quadratic variation?

Answer 1

The 2nd one

Answer 2

20.gif because it goes up 2,4,6,8

Answer 3

Any questions??

Answer 4

that's the right answer, but not the right reason!

Answer 5

welp give her the right reason lol i juss wanna make sure she has a clear understanding of it

Answer 6

20 has

x 1 2 3 4
y 2 8 18 32

a quadratic variation will be of the form y = kx^2 where k is a constant

2 = k(1)^2 2 = k(1) k = 2
8 = k(2)^2 8 = k(4) k = 2
18 = k(3)^2 18 = k(9) k = 2
32 = k(4)^2 32 = k(16) k = 2

Answer 7

so the data in the table in 20 will fit y = kx^2 if k = 2. therefore, it is a quadratic variation.

Answer 8

y varies directly with x2 and y = 48 when x = 2.

Answer 9

y = 4x^2
y = 12x^2
y = 4x
y = x^2 + 25

Answer 10

y=12x^2

Answer 11

substitute 2 in for x and u have 12(2)^2 then follow PEMDAS so exponents comes first so 2^2 is 4 and 12*4 =48 this the answer is y=12x^2

Answer 12

Which relationship shows an inverse variation?

Answer 13

y = kx is direct variation
y = k/x is indirect variation

Answer 14

indirect variation implies that as one quantity increases, the other must decrease

Answer 15

that alone is enough to solve this one.

Answer 16

C?

Answer 17

as x goes from 1 to 4, f(x) goes from 12 to 3, so that passes the "one increases, the other decreases" test.

f(x) = k/x

12 = k/1
6 = k / 2
4 = k / 3
3 = k / 4

k = 12 solves all of those, so the relationship is f(x) = 12/x and it is indirect variation.