Question

Let N = a2607b be a six digit number divisible by 75, then ‘a’ can not be equal to

Answer 1

sicne the given number is divisible by \(75\),
that means it is divisible by both \(25\) and \(3\)

Answer 2

for it to bei divisible by 25, it requires last two digits to be 00/25/50/75
since the previous digit is fixed at 7, \(b = 5\)

Answer 3

so, \(N=a26075\) is divisble by \(25\) for all values of \(a\)

next see wat values of \(a\) will make \(N\) to be divisible by 3 also

Answer 4

remember the divisibility rule for 3 ?

Answer 5

nope

Answer 6

here it is :
if the sum of digits are divisible by 3, then the number is divisible by 3

Answer 7

for \(a26075\) to be divisible by 3, below must hold :

\(a + 2 + 6 + 0 + 7 + 5 \) must be divisible by 3

Answer 8

see for wat values that sum is divisible by 3
or not divisible by 3

hope u can do the rest :)