Question

find the missing factor.
b^2-3b-4=(b-4)(?)

Answer 1

use the quadratic formula

Answer 2

i still dont get it?

Answer 3

Simplifying
b2 + 3b + -4 = 0

Reorder the terms:
-4 + 3b + b2 = 0

Solving
-4 + 3b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-4 + -1b)(1 + -1b) = 0

Subproblem 1
Set the factor '(-4 + -1b)' equal to zero and attempt to solve:

Simplifying
-4 + -1b = 0

Solving
-4 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + -1b = 0 + 4

Combine like terms: -4 + 4 = 0
0 + -1b = 0 + 4
-1b = 0 + 4

Combine like terms: 0 + 4 = 4
-1b = 4

Divide each side by '-1'.
b = -4

Simplifying
b = -4
Subproblem 2
Set the factor '(1 + -1b)' equal to zero and attempt to solve:

Simplifying
1 + -1b = 0

Solving
1 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1b = 0 + -1
-1b = 0 + -1

Combine like terms: 0 + -1 = -1
-1b = -1

Divide each side by '-1'.
b = 1

Simplifying
b = 1
Solution
b = {-4, 1}
does that help?

Answer 4

b^2-3b-4=b^2-(4-1)b-4=b^2-4b+1b-4=b(b-4)+1(b-4)=(b-4)(b-1)
[ 1x-4=-4
4-1=3
4x-1=-4
Write -3=-(4-1) ]

Answer 5

+-b + or - sqrt (b^2 - (4)(a)(c) all divided by 2(a)

-(-3) plus or minus sqrt (-3)^2 - (4)(1)(-4) divided by -2

3 +/_ sqrt 9+16 divided by -2
3 +/- sqrt 25 divided by -2

3 + 5/-2 = -4
3 - 5/-2 = 1
your x values are 1 and -4.

Answer 6

sorry the first part should be -b not +-b typo