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Chemistry 13 Online
OpenStudy (anonymous):

Is E=Mc^2 this as an equation: (3.00*10^8)^2??

OpenStudy (wolfe8):

What you put there is c^2

OpenStudy (abb0t):

I don't get it.

OpenStudy (anonymous):

I thought that when working nuclear equations use E=mc^2, we multiply kg, by (3*10^8m/s)^2

OpenStudy (anonymous):

maybe I was mistaken...

OpenStudy (wolfe8):

Yes that's right, but you only wrote the speed of light in your post. What were you really asking for?

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